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Chapter 50: Answers Explained
There isn't any information in the question that suggests anidase is involved in the equation.
The reaction is not catabolic because it is built up from A and B.
There is no information about the temperature of the surroundings in the question.
Some of the system's heat is lost with each energy transfer.
The choices C and D don't make sense.
The reaction reaches its maximum temperature.
The whole experiment is carried out in an acid environment.
There is no information about the temperature.
The amount of product would be reduced, but the state of the collision would not change.
It would be more difficult to get the reaction to start if the activation energy was raised.
The difference between the PE of the reactants and the PE of the products is called D G. It is unaffected by the absence or presence of enzymes.
The production of B is stopped by D.
The temporary bond between an enzyme and its substrate is a weak one and only lasts for a short time.
It has Van der Waal and hydrogen bonding.
The current model for how the two things bind is not a lock and key, but an idiosyncrasy.
An increase in heat does not increase the number of collisions.
The faster the collision, the less effective it is.
The PE of the transition state is the only difference between the two reactions.
It is lower in some reactions.
Choice A is not correct because the number of effective collisions increases with the number of enzymes.
Choice C is incorrect because of the decrease in energy of activation.
Choice D is not correct because the potential energy of the reactants remains the same.
They are never used up.
The progress of a reaction can't be monitored by the levels of theidases.
The temperature of the system is unaffected by the lower energy needed to begin the reaction.
Choice A is incorrect because the breaking down of a molecule is being built up in this example.
Choice C is not correct because endergonic and endothermic are both related to a reaction that requires or absorbs energy.
The first law of thermodynamics states that energy can only be transferred, released, or absorbed.
Malonate must have prevented succinate from doing it.
According to the description of the experiment, production of fumarate decreased.
Eliminate choices A and B.
There is no product formed when malonate binding to the SDH enzyme.
That is what D shows.
We now know that when the substrate is binding to the enzyme, it causes it to change its shape in order to fit.
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