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Chapter 94: Answers Explained
Round, oval, and long are the names of the animals.
The inheritance is an example of incomplete dominance.
This is the way to solve the problem.
The traits should be considered separately at first.
The height ratio in the offspring is 3:1.
The parents have to be Tt and Tt.
There is a 3:1 ratio of yellow to green in the offspring.
The parents must be Yy and Yy.
Put the two genotypes together.
The parents have to be TtYy and TtYy.
A person with blood type O must have two genes from each parent.
I A i or I B i could be the parents.
They do not have to be type O.
The parents had to have been hybrid and ttss recessive, regardless of which trait was dominant and which was not.
They are a result of two genes exchanging.
It is necessary for genes to be located far apart on a single chromosomes.
Choice B can't be correct because the traits located close together wouldn't undergo crossover.
Choice C cannot be correct because the ratios of the offspring would have been 9:3:3:1.
Choice D doesn't account for the odd results of the 8 and 9 offspring.
For the sex-linked gene, C, which allows for colored pigments, is dominant and C, which prevents colored pigments regardless of the presence of P or p, is the only one.
The female lacks the sex-linked gene for the deposition of pigment in choice A.
She has white eyes.
The male has a dominant C. He has pink eyes because he has at least one dominant P. What is asked in the question is satisfied by that.
There are 44 autosomes and two sex chromosomes for an adult female.
It is true that the sex of the child is determined by the sex of the sperm, but that is irrelevant to the question here.
To find the probability of two independent events, you have to take the chance of one and the chance of the other.
The parents could not produce offspring with the same coat color as choice B.
You can eliminate choice C because it will produce offspring in a 9:3:3:1 ratio, which is not a choice.
choice D is the best choice to produce offspring.
The parents could also be the same.
The mother has the disease and the genes are dominant.
HD is caused by H. Since he does not have the condition, the husband's genotype is pure.
The HD genes are not sex-linked.
All the female offspring are carriers and all the male offspring have white eyes.
The second cross is here.
A male has a 50 percent chance of being white-eyed and a 50 percent chance of being red-eyed.
A female has a 50 percent chance of being white-eyed and a 50 percent chance of being red-eyed.
The sex-linked trait is shown in X-.
The father gives the condition to his daughters.
The daughters do not have the condition because they have a normal X to provide the enzymes that are missing from the impaired X-.
The daughters are not carriers.
Huntington's disease is an inheritable disease.
The F 2 daughter who doesn't have the condition must have one of the healthy genes from her parents.
It can be either I A or I A i.
Since his father has type O blood, person 14 must haveherited the A from his mother and the i from his father.
His genetics are I A i.
There are backcrosses or testcrosses between the guinea pigs.
The black people's genetics are revealed through the matings.
It is most likely that black guinea pig #1 is the dominant one.
If it had been a hybrid, there would have been at least one white child.
The fact that there are several white offspring from the second mating indicates that the second black male, #3, is a hybrid.
You cross the organisms that show the same trait.
If white fur is a recessive trait, and an organism has white fur, you know the organism's genotype by looking at it.
There will never be offspring that show the trait in a testcross if the parent is dominant.
50% of the time, the offspring of a hybrid parent will have white fur.
This is a male.
There is an extra chromosome at the 21st position.
This is a test for Down syndrome.
The normal 23 chromosomes were donated by one gamete.
The extra chromosomes were caused by an error called nondisjunction, in which one pair of chromosomes failed to separate.
A normal meiotic division would produce normal gametes, normal offspring, and a normal karyotype.
Choice B is incorrect because the error occurred during meiosis and the formation of gametes.
Choice D is not correct because the question involved an entire chromosomes.
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